Community Answer

Honor CodeSolved 1 Answer

See More Answers for FREE

Enhance your learning with StudyX

Receive support from our dedicated community users and experts

See up to 20 answers per week for free

Experience reliable customer service

Get Started

Instantaneous centers are given below -At this instant, B C will not be rotating It will only haveTranslation. ( \because Its I.center is at infinite with respect to\therefore Velocity of point \left(I_{13}\right) \quad V_{c}=1.8 \mathrm{~m} / \mathrm{s} fixed Link )\begin{array}{l}c=1.8 \mathrm{~m} / \mathrm{s} \text { towards right. } \\\text { and } \alpha_{B C}=0\end{array}Now, we have a_{B}=0.6 \mathrm{~m} / \mathrm{s}^{2} which is also a point on A B. and I t is a tangential acceleration.\begin{array}{l}\therefore a_{B}=(A B) \alpha_{A B} \quad\left\{\because a_{t}=\gamma \alpha\right\} \text {. } \\0.6=0.3 \times \alpha_{A B 3} \text {. } \\\alpha_{A B}=2 \mathrm{rad} / \mathrm{s}^{2} \\\end{array}Now, \quad V_{B}=1.8 \mathrm{~m} / \mathrm{s}=(A B) \omega_{A B} \quad(\because V=\gamma \omega)\begin{array}{l} 1.8=0.3 \omega_{A B} \\\omega_{A B}=6 \text { rad } / \mathrm{s}^{2} \\a_{\text {radial }}=\omega_{A B}^{2}(A B)=36 \times 0.3=10-8 \mathrm{~m} / \mathrm{s}^{2} \\\therefore \text { Components of velocity } \\a_{B}=a_{t}=0.6 \mathrm{~m} / \mathrm{s}^{2} \text { and } a_{r}=10.8 \mathrm{~m} / \mathrm{s}^{2}\end{array}AB is perpendicular to horizontal line or line of motion of the slider. It means BC will be only translating. We got the same from instantaneous center approach.  ...