(1) Area of cross-section of jet a=(pi)/(4)xx15^(2)a=0.0177m^(2)u=15m//sv=6m//sSpeed of jet normal to plate, with respect to Plate =v_(x)=(u-v)(a) Force = Rate of change of luiear momentum= mass How rate x change in velocity of flow along noermal direction{:[F_(x)=rho a(v_(x))xx(v_(x)-0)],[=rho a(v_(x))^(2)=1000 xx0.0177 xx(15-6)^(2)],[F_(x)=1433.7N]:}Efficiency of Jet =(" Work done by Jet "(J//s))/(" Rate of KE supplied ")Rate of Work done =F_(x)*v=1433.7 xx6=8602.2J//sRate of KE supphied =(1)/(2)m^(˙)u^(2)=(1)/(2)xx rho xx a xx u xxu^(2)=(rho au^(3))/(2)=(1)/(2)xx1000 xx0.0177 xx15^(3)=29868.75J//seta=(8602.2)/(29868.75)=28.8%(b) If the jet is impacted on a serves of blades mounted on a whed. then force exerted by jet in tangential derection{:[F_(t)=rho au xx(u-v)],[=1000 xx0.0177 xx15 xx(15-6)],[=2389.5N]:}Rate of work done ... See the full answer