Question 1- An ultrasonic wave of 3 MHz with an intensity of 10 𝑚𝑊/cm2 isincident on a flat boundary normally between two media withacoustic impedance Z1 and Z2. Assume that the attenuation in thetwo media can be neglected. The reflected power received by anultrasonic transducer with an aperture area of 0.1 cm2 is 0.1𝑚𝑊.(a) What is the transmitted intensity?(b) If Z1 is assumed to be 1.5 × 106 kg/m2-sec, find Z2.(c) Find reflected and transmitted pressure and show that Pi + Pr =Pt(d) Could Pt possibly be greater than Pi? Why?

BNYJNO The Asker · Electrical Engineering

1- An ultrasonic wave of 3 MHz with an intensity of 10 𝑚𝑊/cm2 is incident on a flat boundary normally between two media with acoustic impedance Z1 and Z2. Assume that the attenuation in the two media can be neglected. The reflected power received by an ultrasonic transducer with an aperture area of 0.1 cm2 is 0.1 𝑚𝑊.
(a) What is the transmitted intensity?
(b) If Z1 is assumed to be 1.5 × 106 kg/m2-sec, find Z2.
(c) Find reflected and transmitted pressure and show that Pi + Pr = Pt
(d) Could Pt possibly be greater than Pi? Why?

More
Community Answer
C5LLTJ

I have solved for questions (a), (c) & (d)  Ans.:- Given Dato:An ultersonic wave offrequency =3MHzIntisity =10mW//cm^(2)apperture area =0.1cm^(2) is 0.1mW(a) Incident = Preflected + Prronsinitat.Now,Pincident =10mW∣cm^(2)Preffected =0.1m//N//0.1cm^(2)=1mw//cm^(2)Now, Pransmitted =10-1=9m ... See the full answer