1) Calculate the volume of Ba(OH)2 0.20 M
necessary to neutralize 300.0 mL of
H3PO4 0.30 M.
2)
Reactants X and Y are mixed, each at a concentration of 0.60 mol/L. They react to form P and Z according to the following reaction:
X + Y ⇌ P + Z
(i) At equilibrium, the concentration of X is 0.20 mol/L. Calculate the equilibrium constant. (5 marks)
(ii) What does this value for the Keq mean for the reaction?
Sol:- As per chegg Q & A guidelines, for multiple questions we must answer the first question until the student asked to answer all the questions.The reaction is3Ba(OH)_(2)+2H_(3)PO_(4)rarrBa_(3)(PO_(4))_(2)+6H_(2)ONow, moles of H_(3)PO_(4)= molarity xx volume in litres{:[=0.30 xx300 xx10^(-3)],[=0.09mol]:}Again, moles o ... See the full answer