1. Demonstrate an RL series circuit, by illustration, producing a high voltage by opening the inductive circuit.

2.An inductor connected to a 220volts, 60hertz source has a voltage drop of 132 volts across the resistance of its winding. What is the magnitude and the angle of the voltage across its inductance with respect to the applied voltage?

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This is an series RL cincuit. when switch is at position 1, current is zesco at first and then gradually rises to I_{0}=V / RThe current I in the RL circuit when switched on isI=I_{0}\left(1-e^{-t / r}\right) \text { (twrn }[\tau=4 / R \text {, time } \text { constant }]when switch is in position2, the current drops because of energy dissipation by the pesistor.Gurn onTwen offAn inductor connected to a 220 volt, 60 \mathrm{~Hz} socorce.voltage drop acreoss resistor =132 volt.I R=132 \text { volt }\begin{aligned}\text { voltage drop acruss inductor } & =220-132 \\& =88 \text { volt. }\end{aligned}angle of the voltage accioss its inductance wrot\begin{aligned}\text { applied voltage } & =\sin ^{-1}\left(\frac{88}{220}\right) \\& =\sin ^{-1}\left(\frac{42}{105}\right) \\& =23.57^{\circ} .\end{aligned} ...