Step 1Since you have posted multiple question , as per guidelines we can answer one per session . If you want remaining please repost.In this session , I have solved :Step 2Calculations:I2(s) + 2e----> 2I-(aq) Since iodine is gaining electrons and gain of electrons is termed as reduction .Hence , this is reduction half cell.Multiply this equation with 3.3I2(s) + 6e----> 6I-(aq) ---1C ... See the full answer