Question Solved1 Answer 1. In a circuit the resistance is 12 Q and the inductance is 4 H. The battery gives a constant voltage of 60 V and the switch is closed when t = 0, so the current starts with I(0) = 0. a. Find I(t). b. Find what happens to the current after a long time. c. Find the current after 1 sec.

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Transcribed Image Text: 1. In a circuit the resistance is 12 Q and the inductance is 4 H. The battery gives a constant voltage of 60 V and the switch is closed when t = 0, so the current starts with I(0) = 0. a. Find I(t). b. Find what happens to the current after a long time. c. Find the current after 1 sec.
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Transcribed Image Text: 1. In a circuit the resistance is 12 Q and the inductance is 4 H. The battery gives a constant voltage of 60 V and the switch is closed when t = 0, so the current starts with I(0) = 0. a. Find I(t). b. Find what happens to the current after a long time. c. Find the current after 1 sec.
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Step 1GivenI(0)=0Step 2(a) write KvL along the circuit{:[-V+L(dI)/(dt)+IR=0],[L(dI)/(dt)=V-IR],[ int(dI)/(V-IR)=int(dt)/(L)],[(ln(V-IR))/(-R)=(t)/(L)+c]:}{:[" At "t=0quad I=0],[=>quadC=(ln V)/(-R)]:}{:[(ln(V-IR))/(-R)=(t)/(L)-(ln V)/(R)],[-(1)/(R)(ln(V-IR){:-(ln V)/(R))=(t)/(L)],[ln( ... See the full answer