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Answer: Given Data Let , q = Number of 2004 model cars ordered in August d = Number of 2004 model cars demanded after August Now determine the smallest value of q for which E(q+1)-E(q) >= 0  To calculate E(q+1)-E(q) , consider two possibilities: Case 1 : If d <= q  then in this case , ordering q + 1  units instead of q units which cause to be overstocked by one more unit . The probability that Case 1 will occur is simply P(D <= q) ,  where D is the random variable representing demand. Case 2 : If d >= q+1  then in this case , ordering q + 1  units instead of q units enables to be short one less unit . The probability that  Case 2 will occur is P(D >= q+1)=1-P(D <= q) Now check conditions written above for the give problem. If d <= q , the costs shown in table given below are incurred t tt tttComputation of Total Cost if d <= q ttt  tt tt ttt  tttCost tt tt tttBuy q cars at $10000/car ttt10000q tt tt tttSell d cars at $15000/car ttt-15000d tt tt tttDispose of excess q-d cars at $9000/car ttt-9000(q-d) tt tt tttTotal cost ttt10000q-15000d-9000(q-d) tt t Hence total cost for case d <= q is , 10000 q-15000 d-9000(q-d)=10000 q-15000 d-9000 q+9000 d quad rarr(1)                                                                 =1000 q-6000 d Compare equation (1) with equation , c(d,q) = c_(0)q + (terms not involving q) Hencew C_(0)  is the per - unit cost of being overstocked . Thus get the value C_(0) = 1000 If d >= q+1  , the costs shown in table given below are incurred t tt tttComputation of Total Cost if d >= q+1 ttt  tt tt ttt  tttCost tt tt t ... See the full answer