Question Solved1 Answer 1. Let A and B be events such that P(A) = 0.42 and P(B) = 0.4. Find P(AB) assuming (a) A and B are mutually exclusive. (b) A and B are statistically independent.

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Transcribed Image Text: 1. Let A and B be events such that P(A) = 0.42 and P(B) = 0.4. Find P(AB) assuming (a) A and B are mutually exclusive. (b) A and B are statistically independent.
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Transcribed Image Text: 1. Let A and B be events such that P(A) = 0.42 and P(B) = 0.4. Find P(AB) assuming (a) A and B are mutually exclusive. (b) A and B are statistically independent.
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Solution :-given that,A and B be events.{:[P(A)=0.42],[P(B)=0.4]:}a) A and B are mutually exclusiveWe want to find, P(A∣B)=> We know formula for conditional probability-P(A\\B)=(P(A" and "B))/(P(B))But Here, A and B are mutually exclusive,{:[=>P(A" and "B)=0],[=>P(A∣B)=(P(A" and "B))/(P(B))=(0)/(0.4)=0]:}=>P(A∣B)=0quad([" When "A" and "B" are "],[" mutuall ... See the full answer