Can you please explain how to solve this problem

Thank You.

Community Answer

sol^(n)3x+7y+3=04 Closest point on the given line from the (4,0).Closest distance between two points is the berpendicular distance between them.so line joining to the point from (4,0) will be perpendicular to the given line.rarr let the point on the line is (h,k).it will satisfy the equation.3h+7k+3=0product of slope of two penpendicular line is -1 .[m_(1)m_(2)=-1]solpe of 3x+7y+3=0=>m_(1)=(-[" coefticient of "x" ] ")/(" [coefficient of "y" ] ")=(-3)/(7) slope of (4,0^(x_(1))y_(1)&([x_(2)],[h_(1) ... See the full answer