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Date.(e) p(z <= z_(0))=0.8Page:. using Inverse Noural table the value of z_(0) Conresponding to 0.8 issqrt(z_(0)=0.842)b) quad p(z <= z_(0))=0.25using Inverse Normal table, the value of z_(0) corresponding to 0.25 isc) quad p(z >= z_(0))=0.3{:[:.quad P(z >= z_(0))=1-p(z < z_(0))],[:.quad1-p(z < z_(0))=0.3],[:.quad p(z < z_(0))=1-0.3],[P(z < z_(0))=0.7]:}:. asing fable.z_(0 ... See the full answer