Question Solved1 Answer 11. A particular is moving along the x-axis according to the Law = dax dx +6- + 25x = 0 dt2 dt If the particle started at x = 0 with an initial velocity of 12 ft/sec to the left, determine (a) x in terms oft, (b) the times at which stops occur.
DIZNXJ The Asker · Mechanical Engineering
Transcribed Image Text: 11. A particular is moving along the x-axis according to the Law = dax dx +6- + 25x = 0 dt2 dt If the particle started at x = 0 with an initial velocity of 12 ft/sec to the left, determine (a) x in terms oft, (b) the times at which stops occur.
More Transcribed Image Text: 11. A particular is moving along the x-axis according to the Law = dax dx +6- + 25x = 0 dt2 dt If the particle started at x = 0 with an initial velocity of 12 ft/sec to the left, determine (a) x in terms oft, (b) the times at which stops occur.
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QII{:[(d^(2)x)/(dt^(2))+6(dx)/(dt)+25 x=0],[" at "t=0=>x=0" \& "v=-12" bt isee "],["-ve sign be lebt "],[[(d^(2))/(dt^(2))+6(d)/(dt)+25]x=0],[D^(2)+6D+25=0],[0=(-6+-sqrt(36-100))/(2)],[D=-3+-4i=>alpha=-3","beta=4],[alpha+-i beta],[x=e^(alpha)[c_(1)cos beta t+c_(2)sin be ... See the full answer