Question Solved1 Answer 11. A pendulum has a mass of 1.2 kg, a length of 2.49 meters, and initially at its equilibrium position (vertically down). If it swings through an arc of 29.7 degrees, what is the maximum kinetic energy (in Joules) of the pendulum?

The corner of an infant's bassinet is shown. Determine angles a and B and dimensions a and b of the side and end pieces so the corners of the bassinet will properly meet when assembled. Take d = 10 in. side piece T end 1B Bl" piece 1 in. 2 in. The value of als and the value of Bis The value of a is in, and the value of bis in

Problem 4.11 Part A Use the node-voltage method to find v1 in the circuit(Figure 1) if v 130 V, i 2.2 A Express your answer with the appropriate units. 四? Value Units Submit Request Answer Part B Use the node-voltage method to find 2 in the circuit. Express your answer with the appropriate units. Figure 1 of 1 oz= Value Units Submit Request Answer 4Ω 80Ω Problem 4.11 Part A Use the node-voltage method to find v1 in the circuit(Figure 1) if v 130 V, i 2.2 A Express your answer with the appropriate units. 四? Value Units Submit Request Answer Part B Use the node-voltage method to find 2 in the circuit. Express your answer with the appropriate units. Figure 1 of 1 oz= Value Units Submit Request Answer 4Ω 80Ω Provide Feedback t) 102 5Ω

5. Evaluate the following integrals: a. Sg(+ b)8(t – t)dt -00 b. $(2t? + 8)8(2 – t)dt c. S. cos (2x – 1)]8(3x – 2)dx - Hint: 8(x) is located at x = 0. For example, 8(1-t) is located at 1 – t=0, that is, at t = 1, and so on.

How much heat is released when 36,0 g of water at 20.0°C is cooled to form ice at 20.0°C? Specific heat capacity of H2O(s) - 2.09 J/g.°C Specific heat capacity of H2O(l) - 4.18 J/g.°C Specific heat capacity of H2O(g) - 1.84 J/g.°C Molar mass of H2O - 18.0 g/mol AHtus -6.02kJ/mol AHvap 40.7kJ/mol . . 14.3 kJ 16.6 kJ 18.8 kJ 21.1 kJ 23.3 kJ

Please assist me with the bottom part ONLY! 5Br (aq) + BrO3(aq) + 6H+(aq) + 3Br2(1) + 3H20(1) The above reaction is expected to obey the mechanism: BrO3(aq) + H+(aq) HBrO3(aq) Fast equilibrium HBrO3(aq) + H+ (aq) H2BrO3+ (aq) Fast equilibrium Slow H2BrO3+ (aq) + Br (aq) (Br-BrO2)(aq) + H20 (1) (Br-Bro2)(aq) + 4H+(aq) + 4Br"(aq) kes , products Fast Choose, from the list below, correct expressions for the overall rate law which are completely consistent with the above mechanism. Correct: - d[Br"]/dt = k[Br"][H+]2[BrO3-] Correct: -d[BrO3-]/dt = k[BrO3"][Br"][+]2 Incorrect: d[Br-Bro2]/dt = k[Br"][BrO3"][H+]2 Incorrect: k[BrO 3 ) = -d[Br"]/dt Correct: -d[H+]/dt = k[H+]2[BrO 3 ][Br"] Incorrect: -d[Br"]/dt = k[Br"][BrO 3 ][H+] You are correct. Previous Tries Your receipt no. is 151-3441 For each of the given rate expressions choose the correct expression for the rate constant (k) from the list below. A. K = 5x[(K1+ka+k3)/(k-1+k-2)] B. K = 5x(k1k2k3-k-1k-2) C. K = 6xk3 D. k = [(k1k2k3)/(k-1k-2)] E. K = 6x([(k1k2k3)/(k-1k-2)]) F. none of the above -d[BrO3']/dt -d[Br"]/dt -d[H+]/dt

Point charge q1 = -5.00 nC is on the x-axis at x = -0.400 m. Point P is on the x-axis at x=0.200m. Point charge q2 is at the origin. What are the sign and magnitude of q2 if the resultant electric field at point P is zero? Express your answer in nanocoulombs.