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{:[y=5sec x","y=5cos x","0 <= x <= pi//3;],[" about "y=-5],[" inner radius "=5+5cos x],[" outer radius "=5+5sec x],[" The cross-sectional area is "],[A(x)=pi[(5+5sec x)^(2)-(5+5cos x)^(2)]]:}Hence the volume{:[V=int_(a)^(b)A(x)dx],[=piint_(0)^(pi//3)25[(sec x+1)^(2)-(cos x+1)^(2)]dx]:}{:[=25 piint_(0)^(pi//3)(sec^(2)x+2sec x+1-cos^ ... See the full answer