Question Solved1 Answer Please use the integration method. 12-29. Two cars A and B start from rest at a stop line. Car A has a constant acceleration of a a = 8 m/s2, while car B has an acceleration of ap = (26/2) m/s2, where t is in seconds. Determine the distance between the cars when A reaches a velocity of va = 120 km/h.

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Please use the integration method.

Transcribed Image Text: 12-29. Two cars A and B start from rest at a stop line. Car A has a constant acceleration of a a = 8 m/s2, while car B has an acceleration of ap = (26/2) m/s2, where t is in seconds. Determine the distance between the cars when A reaches a velocity of va = 120 km/h.
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Transcribed Image Text: 12-29. Two cars A and B start from rest at a stop line. Car A has a constant acceleration of a a = 8 m/s2, while car B has an acceleration of ap = (26/2) m/s2, where t is in seconds. Determine the distance between the cars when A reaches a velocity of va = 120 km/h.
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CAR-A; ; start from Rest :.U_(A)=0a_(A)=8m//s^(2);quadV_(A)=120(km)/(h)=33.33m//s.Time Taken to reach V_(A)=120km//h{:[V_(A)=u_(A)+a_(A)t=>t=(V_(A))/(a_(A))=(33.33)/(8)],[t=4.166sec]:}Distance Travelled by Car-A{:[S_(A)=u_(A)t+(1)/(2)a_(A)t^(2)],[S_(A)=0+(1)/(2)(8)(4.166)^(2)=69.42m]:}S_(A)=69.42mCar"-"Bquada_(B)=2t^(3//2)m//s^(2){:[(dv_(B))/(dt)=a_(B)=>(dv_(B))/(dt)=2t^(3//2)],[dv_(B)=2t^(3//2)dt]:}Integr ... See the full answer