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Step1/1Here is the solution Given datu=>quad{:[=>" at "t=0s=>quadv_(0),=8m//s],[a_(0),=6m//s]:}quad a=-t//4+6=>{:[a=(dv)/(dt)],[adt=dv],[(-(t)/(4)+6)dt=dv]:}take intigration{:[[V]_(v_(0))^(V_("max "))=[(-t^(2))/(8)+6t]_(0)^(t)],[V_("max ")-V_(0)=(-t^(2))/(8)+6t]:}=> velocity will be maximum when a=0 in graph, so t=24 taken in eq (1)V_("max ")-8=( ... See the full answer