Question Solved1 Answer 15 Consider four imaginary metals X, Z, A and Q. a On the basis of the following data, arrange the metals X, Z and Q in order of reactivity (most reactive first): • Z reduces Q2+ to Q • X reduces z2+ to Z b The following reactions also occur: A+Q2+ → A2+ +Q Z+A2+ → Z2+ +A i Is A a stronger or weaker reducing agent than Q? ii Arrange all four metals in order of reducing ability (strongest reducing agent first) iii Which of the species, A, A2+, Z, Z2+, Q, Q2+, X, X2+ is the strongest oxidising agent? c An electrochemical cell is set up with a piece of A dipping into a solution of A(NO3)2 in one half-cell and a piece of X dipping into a solution of XSO4 in the other half-cell. i Which way do electrons flow in the external circuit? ii Which is the anode in the cell? jii Write the cell notation for this cell. iv The X|XSO4 half-cell is replaced by a ZIZSO4 half-cell. Will the voltage be higher or lower than that in the original cell?
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Answer: a. Zreduces varphi^(2+) to varphi{:[z+varphi^(2+)longrightarrowz^(2+)+varphi],[x" reduces "z^(2+)t_(0)z],[x+z^(2+)longrightarrowx^(2+)+z]:}So onden of reactivity isx > z > 9xx can reduce both z^(2+)&varphi^(2+) 15S. The reactions given ane -{:[A+Q^(2+)longrightarrowA^(2+)+Q],[z+A^(2+)longrightarrowZ^(2+)+A]:}i. Since A can reduce Q^(2+) and also Q^(2+) is reduced ley the other metals, hence A is a stronger reducing agent than S.i2. From the above reactions it is concheded that the neducing ability of the metals ane in the following orden -x > z > A > Qx can reduce z^(2+),A^(2+),varphi^(2+)Z can reduce A^(2+),varphi^(2+)A can reduce only rho^(2+)iii. The specisn given ane -A,A^(2+),z,z^(2+),varphi,varphi^(2+),x,x^(2+).The stnongest oxidizing agent is that species which is neduced most easily. It means the species that can easily accept electrons to get reduced. So this oxidizing ag ... See the full answer