Question Solved1 Answer Thermodynamics: Please show step by step solution for the following Practice problem 16. The pressure on 142 1/min of air is boosted reversibly from 2068.44 kPaa to6205.32 kPaa while the temperature remains constant at 24 °C. Find W if theprocess is nonflow.a. -222.6 kJ/minb. -223.7 kJ/min c. -322.6 kJ/min d.324 kJ/min

V55D1D The Asker · Mechanical Engineering
Thermodynamics: Please show step by step solution for the following Practice problem
Transcribed Image Text: 16. The pressure on 142 1/min of air is boosted reversibly from 2068.44 kPaa to6205.32 kPaa while the temperature remains constant at 24 °C. Find W if theprocess is nonflow.a. -222.6 kJ/minb. -223.7 kJ/min c. -322.6 kJ/min d.324 kJ/min
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Transcribed Image Text: 16. The pressure on 142 1/min of air is boosted reversibly from 2068.44 kPaa to6205.32 kPaa while the temperature remains constant at 24 °C. Find W if theprocess is nonflow.a. -222.6 kJ/minb. -223.7 kJ/min c. -322.6 kJ/min d.324 kJ/min
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Step 1Guiven Data,{:" Cuiven Data, "{:[P_(1)=2068.44kPa","P_(2)=6205.32kPa","V_(1)=142l_(min)],[=0.142m^(3)//m],[" Temp "T=24^(@)C" (Constant) "]:}:}Step 2Now, for isothermal procers, ... See the full answer