Given dataThe ratio of diameters (D_(1))/(D_(2))=4.26The density oil is rho_("oil ")=873The density mercury rho=13600kg//m^(3)The difference between level in manometer Delta h=1.81cm(a)Using continuity equation{:[A_(1)v_(1)=A_(2)v_(2)],[(v_(2))/(v_(1))=(A_(1))/(A_(2))],[=(D_(1)^(2))/(D_(2)^(2))],[=(4.6)^(2)],[=21.16=R]:}(b)The pressure is{:[P=P_(1)-P_(2)],[=rho gh],[=(13600)(9.8)(1.81 xx10^(-2))], ... See the full answer