Question Solved1 Answer (17\%) Problem 1: A Venturi meter is a horizontal tube with a wide section and a narrow section, each of which is attached to a vertical tube. The pressure difference between the vertical tubes, caused by fluid moving through the horizontal tube, is measured with a U-tube manometer. For the device shown, assume the ratio between the diameters is \( 4.26 \). (17\%) Problem 1: A Venturi meter is a horizontal tube with a wide section and a narrow section, each of which is attached to a vertical tube. The pressure difference between the vertical tubes, caused by fluid moving through the horizontal tube, is measured with a U-tube manometer. For the device shown, assume the ratio between the diameters is 4.26. Additionally assume that the fluid in the U-tube manometer is mercury with a density of 13,600 kg/m3. Suppose that the fluid moving through the horizontal section is oil with a density of 873 kg/m3, and the difference between the mereury levels on the left-hand and right-hand sides of the manometer is 1.81 cm.

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Transcribed Image Text: (17\%) Problem 1: A Venturi meter is a horizontal tube with a wide section and a narrow section, each of which is attached to a vertical tube. The pressure difference between the vertical tubes, caused by fluid moving through the horizontal tube, is measured with a U-tube manometer. For the device shown, assume the ratio between the diameters is 4.26. Additionally assume that the fluid in the U-tube manometer is mercury with a density of 13,600 kg/m3. Suppose that the fluid moving through the horizontal section is oil with a density of 873 kg/m3, and the difference between the mereury levels on the left-hand and right-hand sides of the manometer is 1.81 cm.
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Transcribed Image Text: (17\%) Problem 1: A Venturi meter is a horizontal tube with a wide section and a narrow section, each of which is attached to a vertical tube. The pressure difference between the vertical tubes, caused by fluid moving through the horizontal tube, is measured with a U-tube manometer. For the device shown, assume the ratio between the diameters is 4.26. Additionally assume that the fluid in the U-tube manometer is mercury with a density of 13,600 kg/m3. Suppose that the fluid moving through the horizontal section is oil with a density of 873 kg/m3, and the difference between the mereury levels on the left-hand and right-hand sides of the manometer is 1.81 cm.
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Given dataThe ratio of diameters (D_(1))/(D_(2))=4.26The density oil is rho_("oil ")=873The density mercury rho=13600kg//m^(3)The difference between level in manometer Delta h=1.81cm(a)Using continuity equation{:[A_(1)v_(1)=A_(2)v_(2)],[(v_(2))/(v_(1))=(A_(1))/(A_(2))],[=(D_(1)^(2))/(D_(2)^(2))],[=(4.6)^(2)],[=21.16=R]:}(b)The pressure is{:[P=P_(1)-P_(2)],[=rho gh],[=(13600)(9.8)(1.81 xx10^(-2))], ... See the full answer