Question Solved1 Answer 1)A saturated solution 250 mL of AgCH3COO was evaporated to dryness. Once dry the sample was found to contain 1.84 g AgCH3COO. Calculate the solubility product constant for AgCH3COO. 2) The molar solubility of Pb₃(PO₄)₂ is 6.3x10-12. Find its Ksp. Please show your work. Complete this question on paper. To let me see your answer: open Google Drive and press the "+" button (lower right on an iPad) choose "Use Camera" and take a photograph of your answer locate your file, and then press the "..." turn link sharing on copy link go back to the quiz paste the link into the textbox (hold your finger down and then select paste)

WY4K8M The Asker · Chemistry

1)A saturated solution 250 mL of AgCH3COO was evaporated to dryness. Once dry the sample was found to contain 1.84 g AgCH3COO. Calculate the solubility product constant for AgCH3COO.

2)

The molar solubility of Pb₃(PO₄)₂ is 6.3x10-12. Find its Ksp.

Please show your work. Complete this question on paper. To let me see your answer:

  • open Google Drive and press the "+" button (lower right on an iPad)
  • choose "Use Camera" and take a photograph of your answer
  • locate your file, and then press the "..."
  • turn link sharing on
  • copy link
  • go back to the quiz
  • paste the link into the textbox (hold your finger down and then select paste)
More
See Answer
Add Answer +20 Points
Community Answer
6OLCXS The First Answerer
See all the answers with 1 Unlock
Get 4 Free Unlocks by registration

Answer 1 - The solubility product constant for AgCH3COO = 1.94 × 10-3 . Explanation -  Answer rarrWe know that[" mol "=(" Given mass ")/(" molar mass ")]Since, molar mass of Ag CH_(3)COOrarr166*91g//mol.mol=(1.84)/(166.91)=0.0110molAgCH_(3)COOConcentration =>(0.0110(mol))/(250(L)xx0^(-3)(L))=0.0441(mol)/(L)AgctbCO0{:[AgCH_(3)COO_((s)),⇌Ag^(+)(aq) +CH_(3)COO_((aq) )],[0.0441,0.0441],[k_(sp),=[Ag^(+)][CH_(3)COO^(-)]],[ ... See the full answer