Question 2. (4 MARKS) True or False and WHY? (without the correct "WHY" this maxes out to 0 (zero)). If \( \mathbb{P} \) is a relation and \( \operatorname{dom}(\mathbb{P}) \) is a set then \( \mathbb{P} \) is a set.

ZRFVHV The Asker · Advanced Mathematics

Transcribed Image Text: 2. (4 MARKS) True or False and WHY? (without the correct "WHY" this maxes out to 0 (zero)). If \( \mathbb{P} \) is a relation and \( \operatorname{dom}(\mathbb{P}) \) is a set then \( \mathbb{P} \) is a set.
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Transcribed Image Text: 2. (4 MARKS) True or False and WHY? (without the correct "WHY" this maxes out to 0 (zero)). If \( \mathbb{P} \) is a relation and \( \operatorname{dom}(\mathbb{P}) \) is a set then \( \mathbb{P} \) is a set.
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【General guidance】The answer provided below has been developed in a clear step by step manner.Step1/1The statement "If P is a relation and dom(P) is a set then P is a set" is actually false.A relation is a set of ordered pairs, where each ordered pair represents a relationship between two elements. However, not all sets of ordered pairs are relations.For a set of ordered pairs to be a relation, it must satisfy the following condition: If (a,b)and(a,c) are in the set, then b=c. This condition ensu ... See the full answer