Community Answer

(A) Given that Mass of women =64kg Mass of stone =0.1kg Velocity of women =0.0017m/s (in the forward direction) We know that if Fext =0 (external forces are zero) then linear momemtum of the system will be conserved. i.e, Pi =Pf Initial velocity of the women =0 m/s Initial velocity of the stone =0m/s Therefore, Total linear momemtum of the women and stone =0kgm/s (B) Let's us consider velocity of the stone after the kick by women =V m/s Linear momemtum{ P =M.V} (C) Linear momemtum of the women after kick =64*0.0017=0.1088kgm/s Linear momemtum of ston ... See the full answer