Question 2) A 64-kg woman stands on frictionless level ice with a 0.10-kg stone at her feet. She kicks the stone with her foot so that she acquires a velocity of 0.0017 m/s in the forward direction. a) What is the total momentum of the women and the stone before the kick? b) What is the total momentum of the women and the stone after the kick? c) What is the momentum of the women after the kick? d) What is the velocity acquired by the stone? Give both magnitude and direction

IX40I0 The Asker · Calculus

Transcribed Image Text: 2) A 64-kg woman stands on frictionless level ice with a 0.10-kg stone at her feet. She kicks the stone with her foot so that she acquires a velocity of 0.0017 m/s in the forward direction. a) What is the total momentum of the women and the stone before the kick? b) What is the total momentum of the women and the stone after the kick? c) What is the momentum of the women after the kick? d) What is the velocity acquired by the stone? Give both magnitude and direction
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Transcribed Image Text: 2) A 64-kg woman stands on frictionless level ice with a 0.10-kg stone at her feet. She kicks the stone with her foot so that she acquires a velocity of 0.0017 m/s in the forward direction. a) What is the total momentum of the women and the stone before the kick? b) What is the total momentum of the women and the stone after the kick? c) What is the momentum of the women after the kick? d) What is the velocity acquired by the stone? Give both magnitude and direction
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(A) Given that Mass of women =64kg Mass of stone =0.1kg Velocity of women =0.0017m/s (in the forward direction) We know that if Fext =0 (external forces are zero) then linear momemtum of the system will be conserved. i.e, Pi =Pf Initial velocity of the women =0 m/s Initial velocity of the stone =0m/s Therefore, Total linear momemtum of the women and stone =0kgm/s (B) Let's us consider velocity of the stone after the kick by women =V m/s Linear momemtum{ P =M.V} (C) Linear momemtum of the women after kick =64*0.0017=0.1088kgm/s Linear momemtum of ston ... See the full answer