Question Solved1 Answer ​​​​​​​ 2) Consider the starting material \( C \) in the reaction depicted in scheme Q2a, which is comverted into 3 pessible products D, E and F that have the same molecular formula. \[ \frac{\mathrm{NeOH}}{\text { in walar }}=\mathrm{D}+\mathrm{E}+\mathrm{F} \] Campound \( F \), also reacts with \( G \) under heat conditions (or UV light) to produce \( H \), as shaw in Scheme Q2b. Scheme Q2b a) What are the names of the reactions depicted in \( \operatorname{Sch} \theta m \theta 8 \) Q2a and Q2b? (2 marks) b) Draw the structures of D, E and F. \( (2+2 \) marks \( ) \) c) What is the relationship between D, E and F? (2 marks) d) What are the respective roles of \( F \) and \( G \) in the reaction an Scheme Q2b? (2 marks) e) The anly bromine canlaining product of the complete cambustion of compaund \( C \) is bromine (Br2). Write a balanced reaction, including state symbols, for the compleie combustian of compound \( C \) in oxygen. Assume that compound \( C \) is in a crystaline fiprrm. (3 marka)

JTXHXS The Asker · Chemistry

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Transcribed Image Text: 2) Consider the starting material \( C \) in the reaction depicted in scheme Q2a, which is comverted into 3 pessible products D, E and F that have the same molecular formula. \[ \frac{\mathrm{NeOH}}{\text { in walar }}=\mathrm{D}+\mathrm{E}+\mathrm{F} \] Campound \( F \), also reacts with \( G \) under heat conditions (or UV light) to produce \( H \), as shaw in Scheme Q2b. Scheme Q2b a) What are the names of the reactions depicted in \( \operatorname{Sch} \theta m \theta 8 \) Q2a and Q2b? (2 marks) b) Draw the structures of D, E and F. \( (2+2 \) marks \( ) \) c) What is the relationship between D, E and F? (2 marks) d) What are the respective roles of \( F \) and \( G \) in the reaction an Scheme Q2b? (2 marks) e) The anly bromine canlaining product of the complete cambustion of compaund \( C \) is bromine (Br2). Write a balanced reaction, including state symbols, for the compleie combustian of compound \( C \) in oxygen. Assume that compound \( C \) is in a crystaline fiprrm. (3 marka)
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Transcribed Image Text: 2) Consider the starting material \( C \) in the reaction depicted in scheme Q2a, which is comverted into 3 pessible products D, E and F that have the same molecular formula. \[ \frac{\mathrm{NeOH}}{\text { in walar }}=\mathrm{D}+\mathrm{E}+\mathrm{F} \] Campound \( F \), also reacts with \( G \) under heat conditions (or UV light) to produce \( H \), as shaw in Scheme Q2b. Scheme Q2b a) What are the names of the reactions depicted in \( \operatorname{Sch} \theta m \theta 8 \) Q2a and Q2b? (2 marks) b) Draw the structures of D, E and F. \( (2+2 \) marks \( ) \) c) What is the relationship between D, E and F? (2 marks) d) What are the respective roles of \( F \) and \( G \) in the reaction an Scheme Q2b? (2 marks) e) The anly bromine canlaining product of the complete cambustion of compaund \( C \) is bromine (Br2). Write a balanced reaction, including state symbols, for the compleie combustian of compound \( C \) in oxygen. Assume that compound \( C \) is in a crystaline fiprrm. (3 marka)
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Step1/5.gkwtCW{margin:0;font-family:"Aspira Webfont","Helvetica","Arial",sans-serif;display:-webkit-box;display:-webkit-flex;display:-ms-flexbox;display:flex;-webkit-flex-direction:column;-ms-flex-direction:column;flex-direction:column;gap:16px;}/*!sc*/data-styled.g367[id="sc-z3f5s1-0"]{content:"gkwtCW,"}/*!sc*/.iIwMoS{white-space:pre-wrap;}/*!sc*/data-styled.g369[id="sc-1aslxm9-0"]{content:"iIwMoS,"}/*!sc*/.fzJtOB{text-align:start;}/*!sc*/data-styled.g371[id="sc-1aslxm9-2"]{content:"fzJtOB,"}/*!sc*/.hOZehF{margin:0;font-family:"Aspira Webfont","Helvetica","Arial",sans-serif;}/*!sc*/data-styled.g398[id="sc-9wsboo-0"]{content:"hOZehF,"}/*!sc*/.lhIoTe{margin:0;font-size:1rem;}/*!sc*/data-styled.g400[id="sc-1swtczx-0"]{content:"lhIoTe,"}/*!sc*/.dirqSb{margin:0;font-family:"Aspira Webfont","Helvetica","Arial",sans-serif;}/*!sc*/data-styled.g429[id="sc-1wwe652-0"]{content:"dirqSb,"}/*!sc*/.dZTFxH{background-color:#fff;font-size:16px;}/*!sc*/data-styled.g430[id="sc-1wwe652-1"]{content:"dZTFxH,"}/*!sc*/.kZhTRC{-webkit-user-select:none;-moz-user-select:none;-ms-user-select:none;user-select:none;}/*!sc*/data-styled.g431[id="sc-1wwe652-2"]{content:"kZhTRC,"}/*!sc*/.iHelzO{margin:0;font-family:"Aspira Webfont","Helvetica","Arial",sans-serif;line-height:normal;}/*!sc*/data-styled.g433[id="sc-1sugbjn-0"]{content:"iHelzO,"}/*!sc*/.kkKaFK{margin-top:14px;}/*!sc*/data-styled.g437[id="sc-1sugbjn-4"]{content:"kkKaFK,"}/*!sc*/.iQllJf{margin-top:14px;}/*!sc*/data-styled.g438[id="sc-1sugbjn-5"]{content:"iQllJf,"}/*!sc*/Q-a ; scheme Q2a ; Elimination of reaction alkyl halide under strong base condition E1 & E2 elimination reaction scheme Q2b ; Diels alder reaction ; {4n+2} cyclo addition reaction Explanation:Diels-Alder reaction proceeds through the suprafacial interaction between a 4𝝅 electron system with a 2𝝅 electron system. Diels-Alder reaction involves cycloaddition reaction.Step2/5.gkwtCW{margin:0;font-family:"Aspira Webfont","Helvetica","Arial",sans-serif;display:-webkit-box;display:-webkit-flex;display:-ms-flexbox;display:flex;-webkit-flex-direction:column;-ms-flex-direction:column;flex-direction:column;gap:16px;}/*!sc*/data-styled.g367[id="sc-z3f5s1-0"]{content:"gkwtCW,"}/*!sc*/.iIwMoS{white-space:pre-wrap;}/*!sc*/data-styled.g369[id="sc-1aslxm9-0"]{content:"iIwMoS,"}/*!sc*/.fzJtOB{text-align:start;}/*!sc*/data-styled.g371[id="sc-1aslxm9-2"]{content:"fzJtOB,"}/*!sc*/.hOZehF{margin:0;font-family:"Aspira Webfont","Helvetica","Arial",sans-serif;}/*!sc*/data-styled.g398[id="sc-9wsboo-0"]{content:"hOZehF,"}/*!sc*/.lhIoTe{margin:0;font-size:1rem;}/*!sc*/data-styled.g400[id="sc-1swtczx-0"]{content:"lhIoTe,"}/*!sc*/.dirqSb{margin:0;font-family:"Aspira Webfont","Helvetica","Arial",sans-serif;}/*!sc*/data-styled.g429[id="sc-1wwe652-0"]{content:"dirqSb,"}/*!sc*/.dZTFxH{background-color:#fff;font-size:16px;}/*!sc*/data-styled.g430[id="sc-1wwe652-1"]{content:"dZTFxH,"}/*!sc*/.kZhTRC{-webkit-user-select:none;-moz-user-select:none;-ms-user-select:none;user-select:none;}/*!sc*/data-styled.g431[id="sc-1wwe652-2"]{content:"kZhTRC,"}/*!sc*/.iHelzO{margin:0;font-family:"Aspira Webfont","Helvetica","Arial",sans-serif;line-height:normal;}/*!sc*/data-styled.g433[id="sc-1sugbjn-0"]{content:"iHelzO,"}/*!sc*/.kkKaFK{margin-top:14px;}/*!sc*/data-styled.g437[id="sc-1sugbjn-4"]{content:"kkKaFK,"}/*!sc*/.iQllJf{margin-top:14px;}/*!sc*/data-styled.g438[id="sc-1sugbjn-5"]{content:"iQllJf,"}/*!sc*/Q-b ; The elimination reaction is taken under strong base condition with alkyl bromide .BrNaOH (aq)+Compd D+Compd ECompd FExplanation:step -01 ; Elimination of leaving group i.e., Br- and formation of stable carbocationstep-02; Deprotanation of carbocation intermediate gives rise to saytzeff's product , i.e., more substituted alkene .Step3/5.gkwtCW{margin:0;font-family:"Aspira Webfont","Helvetica","Arial",sans-serif;display:-webkit-box;display:-webkit-flex;display:-ms-flexbox;display:flex;-webkit-flex-direction:column;-ms-flex-direction:column;flex-direction:column;gap:16px;}/*!sc*/data-styled.g367[id="sc-z3f5s1-0"]{content:"gkwtCW,"}/*!sc*/.iIwMoS{white-space:pre-wrap;}/*!sc*/data-styled.g369[id="sc-1aslxm9-0"]{content:"iIwMoS,"}/*!sc*/.fzJtOB{text-align:start;}/*!sc*/data-styled.g371[id="sc-1aslxm9-2"]{content:"fzJtOB,"}/*!sc*/.hOZehF{margin:0;font-family:"Aspira Webfont","Helvetica","Arial",sans-serif;}/*!sc*/data-styled.g398[id="sc-9wsboo-0"]{content:"hOZehF,"}/*!sc*/.lhIoTe{margin:0;font-size:1rem;}/*!sc*/data-styled.g400[id="sc-1swtczx-0"]{content:"lhIoTe,"}/*!sc*/.dirqSb{margin:0;font-family:"Aspira Webfont","Helvetica","Arial",sans-serif;}/*!sc*/data-styled.g429[id="sc-1wwe652-0"]{content:"dirqSb,"}/*!sc*/.dZTFxH{background-colo ... See the full answer