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SolutionGiven \rightarrow 0.5 \mathrm{~K} \mid \mathrm{ft})A is Roller support \} Given in Question. B is Pin supportFrom Equation of Equilibrium\begin{array}{l}\sum F_{V}=0 \Rightarrow R_{A}+R_{B}=0.5 \times 8+8+8 \\R_{A}+R_{B}=20 \mathrm{~K} \text { (I) } \\\sum M \operatorname{about} B=0((\text { the -ve) }) \\21 R_{A}-0.5 \times 8 \times 25-8 \times 14-8 \times 7=0 \\\Rightarrow R_{A}=\frac{268}{21} \quad R_{A}=12.76 \mathrm{~K} \\\end{array}from \mathrm{Eq}^{n}(1)\begin{array}{l}R_{A}+R_{B}=20 \mathrm{~K} . \\R_{B}=20-R_{A}=20-12.76 \\R_{B}=7.24 \mathrm{~K}\end{array} ...