Solved 1 Answer
See More Answers for FREE
Enhance your learning with StudyX
Receive support from our dedicated community users and experts
See up to 20 answers per week for free
Experience reliable customer service
(2) (a)FALSE: because 1+1=2 is true but 2+3=4 is false. (b)TRUE: because false implies false is true and 1+1=3 is false and monkey can is false (c)TRUE:p->q is true if either ~p is true or q is true or both .Since ~p=monkey can't fly is true and therefore p->q is true (d)TRUE: p : 1+1=3 and q : 2+2=4 . Since ~p is true and q is also true ,therefore if p then q is true 3\begin{aligned}(p \rightarrow q) \wedge(p \rightarrow r) & \equiv(\neg p \vee q) \wedge(\neg p \vee r) \\& \equiv \neg p \vee(q \wedge r) \\& \equiv p \rightarrow(q \wedge r)\end{aligned} ...