please, solve them in detail and in a systematic way

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Hi, total number of members=5 i) total number of way "two city member" can be selected= \left(\begin{array}{l}5 \\ 2\end{array}\right)=10 ___ ii) since all the 10 way have unique Number of way ,we can select the members in group of 2 individual. so, A group of two people among 10  group have equal chance of being selected. now, probability that the members Hasan and Ahmad both are selected =Probability that a group in which (Ahmad and Hassan ) both exist=1/10u22480.10 Ansu21921/10 thanks!! ...