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Community Answer

Given; one Cylinder with bore (d) of 0.129mtr and stroke (l) of 0.18 mter operating at (N) 800 rpm uses 0.113kg of fuel (m_(f)) in 4 minites (t); developes a torque of 76N-m(T).(a) Brake specific fuel Consumption. (BSFC) in ((gm)/(kw-har))Required:- Brake pouver in kw*& fuel flom rate in gm//h.Assumption:- Fuel Slou rate & Forque of Engine remains constantCommon for Every peroblemFimmula:- BSFC=((m^(˙)_(f)**1000)/(t**(460)))//((T**2pi N)/(60,000))Solution:-{:[" BSFC "=((0.113**1000)/(4**(60)))//((76**2pi**800)/(60,000))],[=((0.113**60**1000)/(4))//((76**2pi**800)/(60,000))],[=266.2180545]:}Ans:-(b) Brake mean. Effective pressure (BMEP) in KPaRequired:- Brake pouver; suiept volume ... See the full answer