Question Can someone help me solve this?using psice 2.22 The current i, in the circuit in Fig. P2.22 is 2 A. PSPICE a) Find i1. MULTISIM b) Find the power dissipated in each resistor. c) Verify that the total power dissipated in the cir- cuit equals the power developed by the 80 V source. Figure P2.22 812 1322 412 3 2012 80 v (+) 342

A 0.2-F capacitor has a voltage waveform v(t) as shown in Figure P3–5. Determine and plot as functions of time the (a) current, (b) power, and (c) energy. 3-5 FIGURE P3-5 vit) 80 V 8 10 t, s

Moments and shear stress 2. The following figure shows all the stresses on a small volume element (of volume dxdydz) in equilibrium. By calculating the moments about the centre of the element and understanding that in equilibrium the total sum of moments around the x, y and z axes are zero, prove that: Txy Tyx Txz = T7x and Tyz Tzy dx буг бу dz Ох бу Оух xy Moments and shear stress 2. The following figure shows all the stresses on a small volume element (of volume dxdydz) in equilibrium. By calculating the moments about the centre of the element and understanding that in equilibrium the total sum of moments around the x, y and z axes are zero, prove that: Txy Tyx Txz = T7x and Tyz Tzy dx буг бу dz Ох бу Оух xy бх dy (Hint: calculate the moments about the centre of the element in the x, y and z axes separately.) 60

7–26. Lagrange multipliers Each function ƒ has an absolute maximum value and absolute minimum value subject to the given constraint. Use Lagrange multipliers to find these values. ƒ(x,y) = x2 subject to x2 + xy + y2 = 3

The Gourmand Cooking School runs short cooking courses at its small campus. Management has identified two cost drivers it uses in its budgeting and performance reports—the number of courses and the total number of students. For example, the school might run two courses in a month and have a total of 65 students enrolled in those two courses. Data concerning the company's cost formulas appear below: Instructor wages Classroom supplies Utilities Campus rent Insurance Administrative expenses Fixed Cost per Cost per Cost per Month Course Student $ 2,960 $280 $1,240 S 80 $4,600 $2,400 $3,600 44 S 5 $ For example, administrative expenses should be $3,600 per month plus $44 per course plus $5 per student. The company's sales should average $890 per student. The company planned to run four courses with a total of 65 students; however, it actually ran four courses with a total of only 57 students. The actual operating results for September appear below: Revenue Instructor wages Classroom supplies Utilities Campus rent Insurance Administrative expenses Actual $ 54,950 $11,120 $ 18,050 $ 1,970 $ 4,600 $ 2,540 $ 3,527 Required: Prepare a flexible budget performance report that shows both revenue and spending variances and activity variances for September. (Indicate the effect of each variance by selecting "F" for favorable, "U" for unfavorable, and "None" for no effect (i.e., zero variance). Input all amounts as positive values.) Required: Prepare a flexible budget performance report that shows both revenue and spending variances and activity variances for September. (Indicate the effect of each variance by selecting "F" for favorable, "U" for unfavorable, and "None" for no effect (i.e., zero variance). Input all amounts as positive values.) Gourmand Cooking School Flexible Budget Performance Report For the Month Ended September 30 Flexible Actual Results Budget Planning Budget Courses 4 Students 57 $ 54,950 Revenue Expenses: Instructor wages Classroom supplies Utilities Campus rent Insurance Administrative expenses Total expense Net operating income 11,120 18,050 1,970 4,600 2,540 3,527 41,807 13,143 $

13) The emf and the internal resistance of a battery are as shown in the figure. If a current of 8.3 A is drawn from the battery when a resistor R is connected across the terminals ab of the battery, what is the power dissipated by the resistor R? - 95.0 V 5.0 92 - - - - - A) 620 W B) 530 W C) 440 W D) 790 W E) 700 W

3. Use Lagrangian multiplier to maximize f(x, y) = x2 subject to x2 + xy + y2 = 3.