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/2.41. Consider the signal \[ x[n]=\alpha^{n} u[n] \text {. } \] (a) Sketch the signal \( g[n]=x[n]-\alpha x[n-1] \). (b) Use the result of part (a) in conjunction with properties of convolution in order to determine a sequence \( h[n] \) such that \[ x[n] * h[n]=\left(\frac{1}{2}\right)^{n}\{u[n+2]-u[n-2]\} . \]
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2.41. Consider the signal \[ x[n]=\alpha^{n} u[n] \text {. } \] (a) Sketch the signal \( g[n]=x[n]-\alpha x[n-1] \). (b) Use the result of part (a) in conjunction with properties of convolution in order to determine a sequence \( h[n] \) such that \[ x[n] * h[n]=\left(\frac{1}{2}\right)^{n}\{u[n+2]-u[n-2]\} . \]
F8JTDJThe Asker · Electrical Engineering
Transcribed Image Text: 2.41. Consider the signal \[ x[n]=\alpha^{n} u[n] \text {. } \] (a) Sketch the signal \( g[n]=x[n]-\alpha x[n-1] \). (b) Use the result of part (a) in conjunction with properties of convolution in order to determine a sequence \( h[n] \) such that \[ x[n] * h[n]=\left(\frac{1}{2}\right)^{n}\{u[n+2]-u[n-2]\} . \]
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Transcribed Image Text: 2.41. Consider the signal \[ x[n]=\alpha^{n} u[n] \text {. } \] (a) Sketch the signal \( g[n]=x[n]-\alpha x[n-1] \). (b) Use the result of part (a) in conjunction with properties of convolution in order to determine a sequence \( h[n] \) such that \[ x[n] * h[n]=\left(\frac{1}{2}\right)^{n}\{u[n+2]-u[n-2]\} . \]
Community Answer
VMSL0O
false
  {:[g(n)=x[n]xx{delta[n]-alpha delta[n-1]}],[x[n]**delta[n-1]-alpha delta[n-2]=delta[n-1]],[x[n]**d[n+1]-alpha delta(n)=delta(n+1)],[x[n]+d[n+2]-alpha delta[n+1]=d[n+2]],[:.x[n]+h[n]=4delta[n+2]+2delta ... See the full answer