Solved 1 Answer
See More Answers for FREE
Enhance your learning with StudyX
Receive support from our dedicated community users and experts
See up to 20 answers per week for free
Experience reliable customer service
At equilibrium: Rate of decay = Rate of production of Nuclei \frac{0.693}{t_{1 / 2}} \times N=R \frac{0.693}{2 \text { days }} \times N=10^{10} \frac{0.693}{2 \times 24 \times 3600 s} \times N=10^{10} N=2.49 \times 10^{15} atoms     ANSWER   ...