Community Answer

Question 1. The equilibrium temperature is 76.307 ^(@)C. Therefore, the correct option is (c). Data usedLatent heat of vapourization for waterL=2260 xx10^(3)J//kgSpecific heat of waters=4.19 xx10^(3)J//Kg*KLet the equilibrirem temperaterce is T^(@)C.The amount of heat released for 2kg of steam at 100^(@)C to come to 2kg of water at T^(0)C is{:[Q_(1)=mL+ms Delta T],[=2xx2260 xx10^(3)+2xx4.19 xx10^(3)(100∼T)],[=4520000J+8380(100-T)J(m=2kg)],[Delta T=(100-T)^ ... See the full answer