Question Solved1 Answer 3. (30P) Total head loss of between Point 1 and Point 2 in the given figure is 9 m. Water is flowing at volumetric flow rate of 0.05 m3/s in Pipe A. All pipes are made of commercial steel. The kinematic viscosity of water is 1.033x10-6 m²/s. Neglecting minor losses, find the volumetric flow rate in Pipe B. The length and diameter of pipes are given on the figure. (Note: If iteration is required, stop after the second iteration.) Pipe B L = 266 m, d = 160 mm Pipe A L = 300 m d=200 mm Pipe D L = 510 m d=250 mm Pipe C L = 190 m

WRK369 The Asker · Mechanical Engineering

Transcribed Image Text: 3. (30P) Total head loss of between Point 1 and Point 2 in the given figure is 9 m. Water is flowing at volumetric flow rate of 0.05 m3/s in Pipe A. All pipes are made of commercial steel. The kinematic viscosity of water is 1.033x10-6 m²/s. Neglecting minor losses, find the volumetric flow rate in Pipe B. The length and diameter of pipes are given on the figure. (Note: If iteration is required, stop after the second iteration.) Pipe B L = 266 m, d = 160 mm Pipe A L = 300 m d=200 mm Pipe D L = 510 m d=250 mm Pipe C L = 190 m
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Transcribed Image Text: 3. (30P) Total head loss of between Point 1 and Point 2 in the given figure is 9 m. Water is flowing at volumetric flow rate of 0.05 m3/s in Pipe A. All pipes are made of commercial steel. The kinematic viscosity of water is 1.033x10-6 m²/s. Neglecting minor losses, find the volumetric flow rate in Pipe B. The length and diameter of pipes are given on the figure. (Note: If iteration is required, stop after the second iteration.) Pipe B L = 266 m, d = 160 mm Pipe A L = 300 m d=200 mm Pipe D L = 510 m d=250 mm Pipe C L = 190 m
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Solution:{:" Pipe-c "quad d=250mm:}rarr Parallel conrection flow problemrarr Griven:{:[Q_(A)=0.05m^(3)//s],[(V)_("water ")=1.033 xx10^(-6)m^(2)//s],[Q_(B)=?]:}=> For parallel flow problem, we know-{:[rarrQ_(A)=Q_(B)+Q_(C)-(D],[=>quadh_(f_(A))=h_(f_(B))=h_(f_(C))-11],[rarr(fL_(A)Q_(A))/ ... See the full answer