Question Solved1 Answer Total head loss ofbetween Point 1 and Point 2 in the given figure is 9 m. Water isflowing at volumetric flow rate of 0.05 m3/s in Pipe A. Allpipes are made of commercial steel. The kinematic viscosity ofwater is 1.033x10-6 m2/s. Neglecting minor losses, findthe volumetric flow rate in Pipe B. The length and diameter ofpipes are given on the figure. (Note: If iteration isrequired, stop after the second iteration.) 3. (30P) Total head loss of between Point 1 and Point 2 in the given figure is 9 m. Water is flowing at volumetric flow rate of 0.05 m°/s in Pipe A. All pipes are made of commercial steel. The kinematic viscosity of water is 1.033x10-6 m²/s. Neglecting minor losses, find the volumetric flow rate in Pipe B. The length and diameter of pipes are given on the figure. (Note: If iteration is required, stop after the second iteration.) Pipe B L = 266 m, d = 160 mm Pipe A Pipe D L = 300 m d=200 mm L = 510 m d=250 mm Pipe C L = 190 m
Total head loss of
between Point 1 and Point 2 in the given figure is 9 m. Water is
flowing at volumetric flow rate of 0.05 m3/s in Pipe A. All
pipes are made of commercial steel. The kinematic viscosity of
water is 1.033x10-6 m2/s. Neglecting minor losses, find
the volumetric flow rate in Pipe B. The length and diameter of
pipes are given on the figure. (Note: If iteration is
required, stop after the second iteration.)
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Sol:- Given data,ppe Bvolumetric flow rate on Dischcage Q_(A)=0.05m//sKinematic viscosty of water (gamma)=1.033 xx10^(-6)m^(2)//sFIND:- volumetric Flow rate in pipe(B), Q_(B)= ?We know that,For parallel flow problem{:[Q_(A)=Q_(B)+Q_(C)rarr" (1) "],[h_(f_(A))=h_(f_(B))=h_(f_(C))rarr" (2) "],[(flAQ_(A)^(2))/(121d_(A)^(5))=(fl_(B)*G_(B)^(2))/(12 ... See the full answer