Question Solved1 Answer 3. (4 points) Given that -2 is a root of x³ +4x²+x-6= 0, find the other root(s). 3. (4 points) Given that -2 is a root of x³ +4x²+x-6= 0, find the other root(s).

1SUA6T The Asker · Precalculus

Transcribed Image Text: 3. (4 points) Given that -2 is a root of x³ +4x²+x-6= 0, find the other root(s).
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Transcribed Image Text: 3. (4 points) Given that -2 is a root of x³ +4x²+x-6= 0, find the other root(s).
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Siven -2 is rook of x^(3)+4x^(2)+1-6=0. so, -2 sateffy the given eqn.{:[(-2)^(3)+4xx(-2)^(2)+(-2)-6],[=-8+16-8],[=-16+16],[=0]:}{:[x^(2)+2x ... See the full answer