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Given: Radius of the loop (r) = 10 cm = 0.01 m Resistance of the wire (R) = 2 ohm Rate at which the magnetic field is increasing (B) = 0.1 T/s   The magnitude if the induced current in the loop will be given by; I=\frac{B \pi r^{2}}{R} I=\frac{0.1 \pi(0.01)^{2}}{2} I=1.57 * 10^{-5} A   (For any doubts about the solution feel free to ask in the comments) ...