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Let  X=undergraduate course  Y=graduate courses In the given problem it says that there should be atleast 30 undergraduate courses and 20 graduate courses i. e X=>30 Y=>20 And there should be atleast 60 courses offered in total  i. e X+y=>60 Each undergraduate courses and graduate courses cost an average of SAR 2500 and SAR 3000 respectively.  We can write it as  Z(total cost) =2500x+3000y Now we will write the question as linear programming problem.  Zmin=2500x+3000y Subject to constraints  X=>30 Y=>20 X+Y=>60 Now replace all inequality constraints by equation  X=30 Y=20 X+Y=60 Now we draw the graph and find the feasible region which satisfy the constraints    Now we see that the point A(40,20) and B(30,30) are in the feasible region.  Now we se that which will minimise Z If we put point A i. e X=40 and Y=20 then             Z= 2500*40+3000*20 Z=1,60,000 If we put point B i. e X=30 and Y=30 Z=2500*30+3000*30 Z=1,65,000 Here we see that min value of z is 1,60,600.  Hence, we conclude that there should 40 undergraduate courses and 20 graduate courses to minimise faculty salaries.    ...