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Taking all the stresses in tension to be positive and thestresses in compression to be negative. For the first part,calculate the strain in the y-direction with the actual loadingcondition and equate it with the strain in the y-direction when theonly single distributed load is applied in the x-direction. For thesecond part, equate the strain in the z-direction to bezero.  Sol given{:[sigma_(x)=48" kips ",nu=0.3],[sigma_(y)=-60" kips ",E=29 xx10^(6)psi],[sigma_(z)=54" kips ",]:}(a) or strainion in y-direction due to actual loading it given by.strain{:[(E_(y))=(sigma_(y))/(E)-(nusigma_(x))/(E)-(nusigma_(z))/(E)],[epsilon_(y)=-(60 xx10^(3))/(29 xx10^(6))-((0.3)(48 xx10^(3)))/(29 ... See the full answer