Question 3. The block is subjected to a triaxial loading as shown. If y = 0.30 and E = 29 x 106 psi, determine the following: a) the single uniformly distributed load (in kips) in the x-direction that would produce the same deformation in the y-direction as the original loading (20 pts, consideration 5 pts); and b) the single uniformly distributed load (in kips) that must be added in the load which exists in the x-direction to produce no deformation in the z-direction. (20 pts, consideration 5 pts). HINT: No deformation in the z-direction means there is no strain in that specific direction but is still subjected to a particular stress. With that, correlating different strains by Poisson's ratio may not be applicable in this part. Use 2 decimal places in every solved value. у 60 kips 48 kips 54 kips z 2" 54 kips 48 kips x v. 3" 60 kips 4"
VGAK0E The Asker · Civil Engineering
Transcribed Image Text: 3. The block is subjected to a triaxial loading as shown. If y = 0.30 and E = 29 x 106 psi, determine the following: a) the single uniformly distributed load (in kips) in the x-direction that would produce the same deformation in the y-direction as the original loading (20 pts, consideration 5 pts); and b) the single uniformly distributed load (in kips) that must be added in the load which exists in the x-direction to produce no deformation in the z-direction. (20 pts, consideration 5 pts). HINT: No deformation in the z-direction means there is no strain in that specific direction but is still subjected to a particular stress. With that, correlating different strains by Poisson's ratio may not be applicable in this part. Use 2 decimal places in every solved value. у 60 kips 48 kips 54 kips z 2" 54 kips 48 kips x v. 3" 60 kips 4"
More Transcribed Image Text: 3. The block is subjected to a triaxial loading as shown. If y = 0.30 and E = 29 x 106 psi, determine the following: a) the single uniformly distributed load (in kips) in the x-direction that would produce the same deformation in the y-direction as the original loading (20 pts, consideration 5 pts); and b) the single uniformly distributed load (in kips) that must be added in the load which exists in the x-direction to produce no deformation in the z-direction. (20 pts, consideration 5 pts). HINT: No deformation in the z-direction means there is no strain in that specific direction but is still subjected to a particular stress. With that, correlating different strains by Poisson's ratio may not be applicable in this part. Use 2 decimal places in every solved value. у 60 kips 48 kips 54 kips z 2" 54 kips 48 kips x v. 3" 60 kips 4"
Community Answer
DL6LKH
Taking all the stresses in tension to be positive and thestresses in compression to be negative. For the first part,calculate the strain in the y-direction with the actual loadingcondition and equate it with the strain in the y-direction when theonly single distributed load is applied in the x-direction. For thesecond part, equate the strain in the z-direction to bezero.  Sol given{:[sigma_(x)=48" kips ",nu=0.3],[sigma_(y)=-60" kips ",E=29 xx10^(6)psi],[sigma_(z)=54" kips ",]:}(a) or strainion in y-direction due to actual loading it given by.strain{:[(E_(y))=(sigma_(y))/(E)-(nusigma_(x))/(E)-(nusigma_(z))/(E)],[epsilon_(y)=-(60 xx10^(3))/(29 xx10^(6))-((0.3)(48 xx10^(3)))/(29 ... See the full answer