Question 3 The planar density of the (112) plane in BCC iron is \( 9.94 * 10^{14} \) atoms \( \mathrm{cm}^{2} \). Calculate (a) the planar density of the (110) plane and (b) the interplanar spacings for both the (112) and (110) planes. On which plane would slip normally occur?

KVEJ2P The Asker · Electrical Engineering

Transcribed Image Text: 3 The planar density of the (112) plane in BCC iron is \( 9.94 * 10^{14} \) atoms \( \mathrm{cm}^{2} \). Calculate (a) the planar density of the (110) plane and (b) the interplanar spacings for both the (112) and (110) planes. On which plane would slip normally occur?
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Transcribed Image Text: 3 The planar density of the (112) plane in BCC iron is \( 9.94 * 10^{14} \) atoms \( \mathrm{cm}^{2} \). Calculate (a) the planar density of the (110) plane and (b) the interplanar spacings for both the (112) and (110) planes. On which plane would slip normally occur?
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KRQSWZ

【General guidance】The answer provided below has been developed in a clear step by step manner.Step1/1Answer.The lattice parameter of the BCC iron, a_{0} = 2.866 * 10 ^ 8 * cm Given that planar density of the 112 plane is, rho_{112} = 9.94 * 10 ^ 14 * atoms / c * m ^ 2...The lattice parameter of the BCC iron, a_(0) ... See the full answer