Design a circuit

Community Answer

【General guidance】The answer provided below has been developed in a clear step by step manner.Step1/1To compare two 3-bit numbers P and Q, we need to check if P is less than Q, i.e., P<Q.We can perform this comparison bit-by-bit starting from the most significant bit. If at any bit position, P has a 0 and Q has a 1, then we can conclude that P<Q. Otherwise, if P has a 1 and Q has a 0 or if P and Q both have the same bit value, then we need to move to the next bit position to perform the comparison.Using this approach, we can design the following sum-of-products circuit ... See the full answer