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(3.8) Given that:The Calibration curve equation of the themistor is:R(T)=0.5e^(-10//T)Omegawhere. T= absolute temperatureTo find:(i) Static sensitivity at 283K(ii) Static Sensitivity at 350K.Solution:Sensitivity of the themistor is the derivative of the Calibration curve equation:{:[" Sensitivity "=(d)/(dT)R(T)],[=(d)/(dT)0.5e^(-(10 )/(T))],[=0.5 xxe^(-(10 )/(T))xx((+10)/(T^(2)))],[=(5xxe^(-10//T))/(T^(2))]:}Static sensitivity is the sensitivity of the thermistor at steady state conditionsHence,Static sensitivity of the thermistor i ... See the full answer