Community Answer

Honor CodeSolved 1 Answer

See More Answers for FREE

Enhance your learning with StudyX

Receive support from our dedicated community users and experts

See up to 20 answers per week for free

Experience reliable customer service

Get Started

(a)Resultant of load \left(1800 \frac{\mathrm{N}}{\mathrm{m}}\right. acts at \frac{1}{3}(1.5) fiom A=\frac{1.5}{3}=0.5 \mathrm{~m}A_{x}Resultant of load \left(600 \frac{\mathrm{N}}{\mathrm{m}}\right) acts \frac{1}{3}(2.5) from B=4-\frac{2.5}{3}=3.17 \mathrm{~m}moment about A \quad \Sigma M_{A}=0\begin{array}{l}B_{y}(4)-\frac{1}{2}(600)(2.5)(3.17)-\frac{1}{2}(1800)(1.5)(0.5) \\=0 \\B y=763.125 \mathrm{~N} \\\sum F_{y}=0 \Rightarrow A y+B y-\frac{1}{2}(1800)(1.5) \\-\frac{1}{2}(600)(2.5)=0 \\A_{y}+763-125-2100=0 \\A y=1336.875 \mathrm{~N} \\\sum f_{x}=0 \Rightarrow A_{x}=0 \\\end{array}(b) Resultant of load ( \left.40 \frac{\mathrm{lb}}{\mathrm{in}}\right) acts at \frac{10}{2} fiom A=5 \mathrm{~m} \mathrm{fiom} AReswlant of load \left(90-40=50 \frac{(b}{\text { in }}\right) acts at \left(\frac{6}{3}\right) from B=2 \mathrm{~m} fiom B=8 \mathrm{~m} fiom A\begin{array}{l} \Sigma F_{y}=0 \Rightarrow 40(10)+\frac{1}{2}(50)(6)-B y=0 \\\Rightarrow B_{y}=550(b) \\\Sigma F_{x}=0 \Rightarrow B x=0 \\\Sigma M=0 \Rightarrow 40(10)(5)+\frac{1}{2}(50)(6)(2)-M_{B}=0 \\\left.M_{B}=0300 \mathrm{~b} . \mathrm{in}\right)\end{array} ...