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Step 1We have given thatn=51, \quad s=0.37, s^{2}=0.1369Confidence Inlerval formula\text { C.I. (Variance })=\left(\frac{(n-1) s^{2}}{x_{u}^{2}}, \frac{(n-1) s^{2}}{x^{2}}\right)Step 2Soln:- The critical values for \alpha=0.05 and d f=n-1=50 are x_{L}^{2}=32,35 and \chi_{U}^{2}=71.42. The corresponding conficlence untereal is computed as\begin{aligned}\text { C.I. (Variance) } & =\left(\frac{(51-1) \times 0.1369}{71.42}, \frac{(51-1) \times 0.1369}{32.35}\right) \\& =(0.0958,0.2115)\end{aligned}\begin{aligned}C \cdot I \cdot(\text { Standard deviation }) & =(\sqrt{0.0958}, \sqrt{0.2115}) \\& =(0.3096,0.4599)\end{aligned} ...