mu=11.6 pounds, sigma=2.8 poundsa){:[P(x > 15)=P((x-11.6)/(2.8) > (15-11.6)/(2.8))],[=P(z > 1.2143)],[=0.1123]:}b){:[P(x < 12)=P((x-11.6)/(2.8) < (12-11.6)/(2.8))],[=P(z < 0.1429)],[=0.5568]:}c){:[P(11 < x < 16)=P((11-11.6)/(2.8) < ( ... See the full answer