Question Solved1 Answer 4.8 FURTHER SIT 120. Replace the loading on the frame by a single force. Specify where its line of action intersects a Vertical line along member AB, measured from A. 4121. Replace the loading on the frame by a single resultant force. Specify where its line of action intersects a horizontal line along member CB. measured from end C. -1 m- 0.5 m 600 NA so 4.8 FURTHER SIT 120. Replace the loading on the frame by a single force. Specify where its line of action intersects a Vertical line along member AB, measured from A. 4121. Replace the loading on the frame by a single resultant force. Specify where its line of action intersects a horizontal line along member CB. measured from end C. -1 m- 0.5 m 600 NA so 10.5 m 400 N 1.5 m 900 N 400 N 1A Probs. 4-120/121

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4-120

Transcribed Image Text: 4.8 FURTHER SIT 120. Replace the loading on the frame by a single force. Specify where its line of action intersects a Vertical line along member AB, measured from A. 4121. Replace the loading on the frame by a single resultant force. Specify where its line of action intersects a horizontal line along member CB. measured from end C. -1 m- 0.5 m 600 NA so 10.5 m 400 N 1.5 m 900 N 400 N 1A Probs. 4-120/121
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Transcribed Image Text: 4.8 FURTHER SIT 120. Replace the loading on the frame by a single force. Specify where its line of action intersects a Vertical line along member AB, measured from A. 4121. Replace the loading on the frame by a single resultant force. Specify where its line of action intersects a horizontal line along member CB. measured from end C. -1 m- 0.5 m 600 NA so 10.5 m 400 N 1.5 m 900 N 400 N 1A Probs. 4-120/121
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Solution:-(1)4-120The free body diagram of the force systemResultant folce along the x-axis{:[SigmaF_(x)=(F_(R))_(x)],[(F_(R))_(x)=(900N)((3)/(5))-(400N)((4)/(5))],[(F_(R))_(x)=220N]:}along the y-axis{:[sumF_(y)=(F_(R))_(y)],[(F_(R))_(y)=(600 N)+(400 N)((3)/(5))-(400 N)-(900 N)((4)/(5))]:}{:[(F_(R))_(y)=-280N],[(F_(R))_(y)=280N(darr)]:}(2)magnitude of the resultant forces{:[F_(R)=sqrt((F_(R))^(2)x+(F_(R))^(2)y)],[=sqrt((220)^(2)+(-280)^(2))],[=sqrt126800],[F_(R)=356.08N]:}Angle of the resultart force with ho ... See the full answer