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Solution: (1) lim_(x rarr3^(-))f(x)=lim_(x rarr3^(+))f(x)=0.5True(2) lim_(x rarr1)f(x)=1!=f(1)=2*5False(3) lim_(x rarr4)f(x)rarr ooquad Trueso it has vertical arymptete at 4(4) lim_(x rarr6^(-))f(x)rarr ooquad so it has vertical asymlim_(x rarr6^(+))f(x)rarr-oo-pt ... See the full answer