A 550kg car is held in place by a light cable ramp. The cable makes an angle of 31 degrees above the surface of the ramp, and the ramp itself rises at 25 degrees above the horizontal.

(A) Find the tension of the cable

(B) What is the normal force the car experiences?

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The above figure is the block diagram.Here, angle of inclination (theta)=25^(@)Angle made by cable above the surface of the ramp (theta^('))=31^(@) Mass of the ear (m)=550kgBy consideringLet T be the tension on the cable(A) By considering the horizontal component of forces{:[T cos theta^(')=mg sin theta.],[=>T=(mg sin theta)/(cos theta^('))]:}Putting the values of m,g,sin theta and cos theta^('){ ... See the full answer