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Solution:- from the following Mechanism.{:[=>I_(2)k_(1)_(k_(1)^('))2I],[2I+H_(2)longrightarrow^(k_(2))2HI]:}Intermediate longrightarrow [I]{:[{:[(d[I])/(dt)=k_(1)[I_(2)]-2k_(1)^(')[I]^(2)-2K_(2)[I]^(2)[H_(2)]],[=0]:}],[" They, "k_(1)[I_(2)]=[I]^(2)(2k_(1)^(')+2k_(2)[H_(2)])], ... See the full answer