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We will be solving this problem with the basic application of Equations of Motions  a) {:[h_("max ")=h_(0)+((v_(f)^(2)-v_(0)^(2)))/(2g)],[h_(0)=" Hight above ground "],[v_(f)=" Final vilouity "],[v_(0)=" Initial "v_(1)" loidy "],[g=-9.8mp],[h_(max)=1.5+((0-(19.6)^(2)))/(-2xx9.8)],[=1.5+19.6],[h_(max)=218.1m.]:}b) speed of the stone will be Iero when it ruaches hmaxc) ... See the full answer