Community Answer

{:[ln 2=epsi(7.0425)xx10^(-5)],[rarr(R)/(K)],[=> =81828.984.8Jascons1-],[R rarr8.3//41(J)/(K)]:}{:[sum_("neg ")=>e^(-(epsi )/(R)((1)/(533)-(1)/(523)))1." change. "],[=>e^(0.353075)-1=y],[Y=0.4234". (Presumed heer that Pressuie) "],[" Su "42.34%" change is obtained fromo "],[" Initial value. "],[" \& this value is in "+m". "],[" 2) Here Pressure Increased "15%],[" which maks "20 xx1.15 rarr23" amm. Tohal Pressue. "],[" Su "A+2B rarr C" Sinch Gases "],[" which makes Pautial Prissure of "A" in "],[" tobelpressue "P_(A)rarrP_(0)//3?]:}au can Replace conc ^(n). formor Rx^(n) to Pressuce,{:[-gamma_(A)=k_(0)e^((-epsi//R_(T)))(P_(0))/(3)((2P_(0))/(3))^(2)],[-gamma_(A)=(z)P_(0)^(3)(z rarrk_(0)e^(-epsi//epsi_(T))(4)/(2))],[-gamma_(A 223am) rarr(z)(23)^(3)],[-gamma_(A 20atm) rarr z(20)^(3)//15%" Mncrak "],[" chanqe "P=(-gamma_( ... See the full answer