Ans:- Free body diagrams mer and as forember AB is can see two force nomber and the tenserum the in from ehe diagrean to weight of equal constant on the Cable.Now, lets Consider the equilbrium iw memser BC.{:[qquadquadsum_(AC)=0;quadF_(AB)((3)/(5))(2)-75(9.81)(2.8)+075(9.81)(0.3)=0],[F_(AB)((6)/(5))-2060.1+2.20.725=0 ... See the full answer